0.006^2+0.6^2=x^2

Solution for 0.006^2+0.6^2=x^2 equation:

0.006^2+0.6^2=x^2

We move all terms to the left:

0.006^2+0.6^2-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+0.360036=0

a = -1; b = 0; c = +0.360036;
Δ = b2-4ac
Δ = 02-4·(-1)·0.360036
Δ = 1.440144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.440144}}{2*-1}=\frac{0-\sqrt{1.440144}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.440144}}{2*-1}=\frac{0+\sqrt{1.440144}}{-2}
=\frac{\sqrt{}}{-2}
$